IU baseball opens B1G Tourney with Iowa

Indiana baseball opens up defense of its Big Ten Tournament title on Wednesday at 6 p.m. ET against No. 8 seed Iowa in Omaha, Neb. The Hoosiers are 3-0 against the Hawkeyes this season.

Top-seeded Indiana baseball opens play in the Big Ten Tournament on Wednesday at 6 p.m. ET against No. 8 seed Iowa at TD Ameritrade Park in Omaha, Neb.

The Hoosiers and Hawkeyes will be the third game of the day. At 10 a.m. ET, No. 3 Illinois faces No. 6 Michigan State, and at 2 p.m. ET No.2 Nebraska takes on No. 7 Ohio State.

After IU and Iowa square off, the final game of the first day of the tournament will feature No. 4 Minnesota against No. 5 Michigan.

If Indiana wins its first game on Wednesday, it would advance to play the winner of Minnesota-Michigan at 10 p.m. ET on Thursday. If the Hoosiers lose the opener, they would play Thursday at 2 p.m. ET.

IU is 3-0 against Iowa this season, having outscored the Hawkeyes 25-9 in those three games that were played April 4-6 in Iowa City. IU won the first game 6-3, then won 14-3 in the second game and 5-3 in the third.

Indiana is the No. 1 seed in the Big Ten Tournament after capturing the regular season conference title for the second year in a row. The Hoosiers are 38-13 overall and 21-3 in conference play heading into the Big Ten Tournament.


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