(William Hauser/USA TODAY Sports)

Buffalo Bills safety Bacarri Rambo was named the AFC Defensive Player of the Week

Bacarri Rambo was named the AFC Defensive Player of the Week on Wednesday.

Almost one year to the day that the Buffalo Bills signed him, safety Bacarri Rambo was named the AFC Defensive Player of the Week. Buffalo's safety played one of the biggest roles in Buffalo's 22-17 win over the New York Jets.

During the course of the game, Rambo made three significant plays. First, Rambo forced a fumble on Devin Smith on a kick return that resulted in a Duke Williams touchdown. The play came immediately following a field goal that had tied the game and gave the Bills a 9-3 lead. In the second half, Rambo continued to help the Bills seize momentum from the Jets.

Following a seven play, 80 yard touchdown drive that put the Bills up 19-3, Rambo forced and recovered a Chris Ivory fumble. This led to a field goal and Buffalo's final points of the game. Fittingly, Rambo ended any chance of a Jets comeback victory when he intercepted Ryan Fitzpatrick at the end of the game. 

Rambo finished the game with three tackles, one pass defensed, one interception, two forced fumbles and one fumble recovery. Rambo, who drew 'Last Blood' on the Jets on Thursday Night Football, was certainly deserving of the award..


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