Burgess AFC Defensive Player of the Week

Oakland Raiders defensive end Derrick Burgess was named AFC Defensive Player of the Week for games played the seventh week of the 2006 season (October 22-23), the NFL announced today.


• Continually disrupting the visiting Cardinals' offense, Burgess tallied 2.0 sacks, shared the team-lead in tackles with five, and deflected a pass that was intercepted in Oakland's 22-9 victory against Arizona.

Leading 7-0 in the first quarter, a charging Burgess leaped to bat a pass in the air, which was intercepted by teammate Terdell Sands. The Raiders capitalized immediately, scoring on a 32-yard touchdown pass on the next play for a 14-0 lead that they would not relinquish.

Both of Burgess' sacks drew 10-yard losses. His other three tackles were all within three yards of the line of scrimmage.

Burgess and the Oakland defense would allow the Cardinals to muster fewer than half of the points they averaged on the season entering the game (18.5) and limited the visitors to one of 11 (nine percent) on third-down conversion tries. Forcing pressure throughout the day, Burgess was a key contributor to Arizona quarterback Matt Leinart's 36.3 passer rating – 48.1 points below his rating prior to Week 7 (84.4).

In his sixth year from Mississippi, this is Burgess' first Player of the Week Award. The 6-2, 260-pounder was named the AFC's Defensive Player of the Month for October last season.

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